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Earlier discussion
1 older comment kept for context.
Favour Onwuchekwa
The man is heterozygous for Haemophilia\( \Rightarrow{Hh} \)
The woman is double recessive for Haemophilia\( \Rightarrow{hh} \)
The result of crossing would be;
Hh Hh hh hh
From the above result we can. deduce that just '2' out of '4' of the offsprings will have the disease "Haemophilia" which implies [½] and in percentage, represents 50%[C].